class Solution:
def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
count = 0
for i in range(len(words)):
flag = 0
for j in range(len(words[i])):
if words[i][j] in allowed:
flag = 0
else:
flag = 1
break
if flag ==0:
count+=1
return count
1002. Find Common Characters | 1602A - Two Subsequences |
1555A - PizzaForces | 1607B - Odd Grasshopper |
1084A - The Fair Nut and Elevator | 1440B - Sum of Medians |
1032A - Kitchen Utensils | 1501B - Napoleon Cake |
1584B - Coloring Rectangles | 1562B - Scenes From a Memory |
1521A - Nastia and Nearly Good Numbers | 208. Implement Trie |
1605B - Reverse Sort | 1607C - Minimum Extraction |
1604B - XOR Specia-LIS-t | 1606B - Update Files |
1598B - Groups | 1602B - Divine Array |
1594B - Special Numbers | 1614A - Divan and a Store |
2085. Count Common Words With One Occurrence | 2089. Find Target Indices After Sorting Array |
2090. K Radius Subarray Averages | 2091. Removing Minimum and Maximum From Array |
6. Zigzag Conversion | 1612B - Special Permutation |
1481. Least Number of Unique Integers after K Removals | 1035. Uncrossed Lines |
328. Odd Even Linked List | 1219. Path with Maximum Gold |